Bourbaki

Example 5

Tag 01LF, permanent. Cite it as [Bourbaki, Tag 01LF].

Topologie algébrique, chapter I, § 1. Produits fibrés et carrés cartésiens

Let (Xi)i∈I(X_i)_{i\in I} and (Yj)j∈J(Y_j)_{j\in J} be families of B-spaces. Let X and Y be their sums. For each (i,j)∈I×J(i, j)\in I\times J, the mapping (x,y)↦(x, y)\mapsto ((i,x),(j,y))((i, x),(j, y)) is a B-isomorphism of Xi×BYjX_i\times_BY_j onto the subspace ({i}×Xi)×B({j}×Yj)(\{i\} \times X_i)\times_B(\{j\} \times Y_j) of X×BYX\times_BY. Since the latter form a partition of X×BYX\times_BY into open subsets, the mapping

h:∐(i,j)∈I×J(Xi×BYj)→X×BY h:\coprod_{(i,j)\in I\times J}(X_i\times_BY_j)\rightarrow X\times_BY

defined by h((i,j),(x,y))=((i,x),(j,y))h((i, j),(x, y)) = ((i, x),(j, y)) is a B-isomorphism.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.