Bourbaki

Definition 5

Tag 01M3, permanent. Cite it as [Bourbaki, Tag 01M3].

Topologie algébrique, chapter I, § 1. Produits fibrés et carrés cartésiens

Let X and Y be topological spaces and f:X→Yf: X\rightarrow Y a mapping. Let R be the equivalence relation associated with ff, and

X→X/R−→gf(X)→Y X\rightarrow X/R-\overset{g}{\rightarrow}f(X)\rightarrow Y

the canonical decomposition of ff (E, II, p. 44). One says that the mapping ff is strict if gg is a homeomorphism, when X/RX/R is endowed with the quotient topology and f(X)f(X) with the topology induced by that of Y.

A strict mapping is continuous.

Let us recall (TG, I, p. 22, prop. 8) that, in order that a mapping ff be strict, it is necessary and sufficient that ff be continuous and that for every open (resp. closed) saturated subset A of X, the set f(A)f(A) be open (resp. closed) in f(X)f(X).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.