Bourbaki

Remark 2

Tag 01OT, permanent. Cite it as [Bourbaki, Tag 01OT].

Topologie algébrique, chapter I, § 4. Revêtements

Let (E,p)(E, p) be a B-space and let (Ei)i∈I(E_i)_{i\in I} be a partition of E consisting of open sets.

If each of the B-spaces (Ei,p∣Ei)(E_i, p|E_i) is a trivializable fibre space, E is a trivializable fibred B-space. In fact, for each i∈Ii\in I, let FiF_i be a topological space such that the B-spaces (Ei,p∣Ei)(E_i, p|E_i) and (B×Fi(B\times F_i, pr1)_1) are isomorphic. Then the B-space (E,p)(E, p) is isomorphic to (B×F(B\times F, pr1)_1), where F is the topological space sum of the family (Fi)i∈I(F_i)_{i\in I}.

Suppose the set I finite. If each of the B-spaces (Ei,p∣Ei)(E_i, p|E_i) is a locally trivial fibred B-space, the same is true of the B-space E. In fact, since the set I is finite, every point of B possesses a neighbourhood U above which the fibred B-spaces EiE_i are all trivializable. By what precedes, the U-space (p−1(U),pU)(\overset{-1}{p}(U), p_U) is then a trivializable fibre space.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.