Bourbaki

Proposition 1

Tag 01OV, permanent. Cite it as [Bourbaki, Tag 01OV].

Topologie algébrique, chapter I, § 4. Revêtements

Let B and E be topological spaces and let p:E→Bp: E\rightarrow B be a mapping. The following conditions are equivalent:

(i) The mapping pp is continuous and the B-space (E,p)(E, p) is a trivializable covering;

(ii) There exists a partition (Vi)i∈I(V_i)_{i\in I} of E consisting of open sets such that, for every i∈Ii\in I, the mapping p∣Vi:Vi→Bp|V_i: V_i\rightarrow B is a homeomorphism.

Suppose that condition (i) is satisfied, and let g:E→B×Fg: E\rightarrow B\times F be a trivialization of the B-space (E,p)(E, p), of fibre type F. Then F is a discrete topological space and the sets Vi=g−1(B×{i})V_i=\overset{-1}{g}(B\times \{i\}), for i∈Fi\in F, form a partition of E consisting of open sets. For every ii, the mapping p∣Vi:Vi→Bp|V_i: V_i\rightarrow B is a homeomorphism, with reciprocal homeomorphism the mapping x↦g−1(x,i)x\mapsto g^{-1}(x, i), whence condition (ii).

Conversely, suppose that condition (ii) is satisfied. The mapping pp is then continuous. Consider the mapping from E into B×IB\times I which associates to x∈Ex\in E the pair (p(x),i)(p(x), i), where ii is the unique element of I such that x∈Vix\in V_i. If I is endowed with the discrete topology, condition (ii) means that this mapping is a B-isomorphism and the B-space (E,p)(E, p) is a trivializable covering.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.