Bourbaki

Proposition 5

Tag 01PE, permanent. Cite it as [Bourbaki, Tag 01PE].

Topologie algébrique, chapter I, § 4. Revêtements

Let B be a topological space, let E and E′E' be B-spaces, and let f:E′→Ef: E'\rightarrow E be a B-morphism. We assume that E is a locally finite covering and that the space E′E', endowed with the mapping ff, is a locally trivial fibred E-space ( resp. a covering). Then, E′E' is a locally trivial fibred B-space ( resp. a covering).

Let us denote by pp and p′p' the respective projections of the B-spaces E and E′E'. Let bb be a point of B. There exists an open neighbourhood U of bb in B and a finite partition (Vi)i∈I(V_i)_{i\in I} of p−1(U)\overset{-1}{p}(U) formed of open sets of E such that, for every i∈Ii\in I, the mapping pp induces a homeomorphism of

ViV_i onto U. Put Vi′=f−1(Vi)V'_i=\overset{-1}{f}(V_i). The sets Vi′V'_i are open in E′E',

form a partition of (−p′1)(U)(^-{p'}^1)(U) and the mapping from Vi′V'_i to U deduced from p′p' by passing to the subspaces makes Vi′V'_i into a locally trivial fibred U-space. It follows that the space (−p′1)(U)(^-{p'}^1)(U), endowed with the mapping

pU′:(−p′1)(U)→Up'_U:(^-{p'}^1)(U)\rightarrow U, is a locally trivial fibred U-space (I, p. 69, remark 2). If (E′,f)(E', f) is a covering of E, the fibres of pU′p'_U are discrete because their intersections with each of the open sets Vi′V'_i are so. This completes the proof.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.