A subset Z of Ω(Γ) is said to be distinguished (relative to the pair (φ,ψ)) if it satisfies the following properties:
(i) For every arrow z of Γ, one has (z,z)∈Z ;
(ii) For every (z1,...,zn)∈ Z, one has (zn,...,z2,z1)∈ Z and (zn,z1,...,zn−1)∈Z ;
(iii) Let z=(z1,...,zn) and z′=(z1′,...,zm′) be elements of Z such that t(zn)=o(z1′). Put zz′=(z1,...,zn,z1′,...,zm′). If two elements among z,z′,zz′ belong to Z, the same is true of the third;
(iv) For every arrow f of H, put φ(f,1)=ψ(f,−1)=φ(f) and φ(f,−1)=ψ(f,1)=ψ(f). Let n be an integer ⩾ 1 and (f1,ε1),...,(fn,εn) a sequence of elements of Fl(H) ×{−1,1} such that ψ(fi,εi)=φ(fi+1,εi+1) for 1⩽i<n and ψ(fn,εn)=φ(f1,ε1); let ai denote the origin of fi and bi its term. In order that ((a1,ε1),...,(an,εn)) belong to Z, it is necessary and sufficient that ((b1,ε1),...,(bn,εn)) belong to Z.
The intersection in Ω(Γ) of every family of distinguished subsets (relative to (φ,ψ)) is again distinguished. In particular, there exists a smallest distinguished subset containing a given subset Z of Ω(Γ).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.