Bourbaki

Proposition 2

Tag 01UK, permanent. Cite it as [Bourbaki, Tag 01UK].

Topologie algébrique, chapter II, § 5. Coégalisateur

If N is a distinguished subgroup of GaG_a, the set of elements z∈Ω(Γ~)\mathbf{z}\in \Omega (\widetilde{\Gamma}) such that c(z)c(\mathbf{z}) is contained in N is a distinguished subset of Ω(Γ~)\Omega (\widetilde{\Gamma}).

Let Z denote the set of elements z∈Ω(Γ~)\mathbf{z}\in \Omega (\widetilde{\Gamma}) such that c(z)⊂Nc(\mathbf{z})\subset N.

Let z∈z\in Fl(Γ~\widetilde{\Gamma}). We have c(z,z)={ea}c(z, z) =\{e_a\} by definition, whence (z,z)∈Z(z, z)\in Z.

Let (z1,...,zn)∈Z(z_1, . . . , z_n)\in Z. By definition of cc, the conjugacy class c(z1,...,zn)c(z_1, . . . , z_n) is equal to c(zn,z1,...,zn−1)c(z_n, z_1, . . . , z_{n-1}) and is formed by the inverses of the elements of c(z‾n,...,z‾1)c(\overline{z}_n, . . . ,\overline{z}_1). This shows that Z satisfies condition (ii).

With the notation of condition (iii), one can choose elements u∈c(z),v∈c(z′)u\in c(\mathbf{z}),v\in c(\mathbf{z}') and w∈c(zz′)w\in c(\mathbf{z}\mathbf{z}') such that uv=wuv=w. If two of the elements u,vu,v and ww belong to N, the same is true of the third, therefore N satisfies (iii).

The notation being that of (iv), we have, for every integer ii such that 1⩽i⩽n1\leqslant i\leqslant n, the relation

φ(fi)h(bi)=h(ai)ψ(fi) \varphi (f_i)h(b_i) =h(a_i)\psi (f_i)

for hh is a homotopy joining φ\varphi to ψ\psi. This equality can also be written

φ~(fi,εi)h(bi)εi=h(ai)εiψ~(fi,εi) \widetilde{\varphi}(f_i, \varepsilon_i)h(b_i)^{\varepsilon_i}=h(a_i)^{\varepsilon_i}\widetilde{\psi}(f_i, \varepsilon_i)

Taking into account the relations ψ~(fi,εi)=φ~(fi+1,εi+1)\widetilde{\psi}(f_i, \varepsilon_i) =\widetilde{\varphi}(f_{i+1}, \varepsilon_{i+1}) for 1⩽i<n1\leqslant i < n and ψ~(fn,εn)=φ~(f1,ε1)\widetilde{\psi}(f_n, \varepsilon_n) =\widetilde{\varphi}(f_1, \varepsilon_1), one deduces

φ~(f1,ε1)h(b1)ε1...h(bn)εn=h(a1)ε1...h(an)εnφ~(f1,ε1) \widetilde{\varphi}(f_1, \varepsilon_1)h(b_1)^{\varepsilon_1}. . . h(b_n)^{\varepsilon_n}=h(a_1)^{\varepsilon_1}. . . h(a_n)^{\varepsilon_n}\widetilde{\varphi}(f_1, \varepsilon_1)

so that the conjugacy classes c((a1,ε1),...,(an,εn))c((a_1, \varepsilon_1), . . . ,(a_n, \varepsilon_n)) and c((b1,ε1),...,(bn,εn))c((b_1, \varepsilon_1), . . . ,(b_n, \varepsilon_n)) are equal. This shows that Z satisfies condition (iv) and completes the proof of the proposition.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.