Bourbaki

Corollary

Tag 01UO, permanent. Cite it as [Bourbaki, Tag 01UO].

Topologie algébrique, chapter II, § 5. Coégalisateur

The groupoid Coeg(φ,ψ\varphi , \psi ) is generated by the image of the morphism γ\gamma.

Let C be the subgroupoid of Coeg(φ,ψ\varphi , \psi ) generated by the image of G; let ii denote the canonical morphism of C into Coeg(φ,ψ\varphi , \psi ) and θ:G→C\theta : G\rightarrow C the morphism such that i∘θ=γi\circ \theta =\gamma. By proposition 2, there exists a unique groupoid morphism θ‾:\overline{\theta}: Coeg(φ,ψ\varphi , \psi )→C\rightarrow C such that θ‾∘γ=θ\overline{\theta}\circ \gamma =\theta. Then γ=i∘θ‾∘γ\gamma =i\circ \overline{\theta}\circ \gamma, hence i∘θ‾i\circ \overline{\theta} is the identity morphism of Coeg(φ,ψ\varphi , \psi ) (loc. cit.). In particular, the mappings Som(ii) and Fl(ii) are surjective, therefore C = Coeg(φ,ψ\varphi , \psi ).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.