such that λ(f)=γo(f) for f∈Go and λ([k])=γ(ck) for k∈K is surjective. Its kernel is the smallest normal subgroup of Go∗F(K) containing the following elements:
Since G is transitive, the mapping which to an element k∈K associates the orbit of (o,k) is a bijection of K onto the set of orbits of H. Thus Orb(G) is identified with {o} and Orb(H) with K. The framework Γ0 of the pair (φ,ψ) is then identified with the quiver having a unique vertex o and whose set of arrows is K. Let T be the subquiver of Γ0 with set of vertices {o} and whose set of arrows is empty; the associated graph is the unique maximal tree of the graph Γ0.
The family (o,(o,k)k∈K,(eo)k∈K,(ck)k∈K,T,o) is a basic equipment of the pair (φ,ψ).
The mapping f↦(f,k) defines an isomorphism of the isotropy group Go onto the isotropy group H(o,k); by means of this isomorphism, the homomorphisms φk and ψk of H(o,k) into Go defined by Prop. 5 of II, p. 208 are given by
(3) φk(f,k)=f et ψk(f,k)=ck−1k∗(f)ck,
for k∈K and f∈Go.
The quiver H×GH is the equalizer in H×H of the quiver morphisms ψ∘ pr1 and φ∘ pr2. Its vertices are the pairs ((a,k),(b,h)) where a and b are vertices of G and k and h elements of K such that b=k∗a, and its arrows are the pairs ((f,k),(g,h)) where f and g are arrows of G, and k and h elements of K such that g=k∗f; the origin of the arrow ((f,k),(g,h)) is equal to ((o(f),k),(o(g),h)); its end is equal to ((t(f),k),(t(g),h)).
One then defines a quiver morphism μ from H×GH into H by putting μ((a,k),(b,h))=(a,kh) and μ((f,k),(g,h))=(f,kh). We have φ∘μ=φ∘ pr1 and ψ∘μ=ψ∘ pr2.
Let x and y be vertices of H such that φ(x)=φ(y). Then there exist a vertex a of G and elements k and h of K such that x=(a,k) and y=(a,h). Put z=(h∗a,h−1k); then μ(y,z)=x. This shows that the pair (φ,ψ) satisfies the hypotheses of Prop. 4 (II, p. 202).
A vertex (a,k) of H belong to the groupoid Ker(φ,ψ ), equalizer of φ and ψ, if and only if k∗a=a, that is to say, if k belong to the stabilizer of the vertex a in the group K. Let A1 be the set of pairs (a,k), for k∈K and a∈Ak; it meets all the orbits of the subgroupoid Ker(φ,ψ ) of H. Let Z1 be the subset of Ω(Γ) formed by the sequences of the form (((a,k),1)), for (a,k)∈A1. For z=((a,k),1)∈Z1,(f(a,k),k) is an arrow of H joining (a,k) to (o,k). Put f(z)=((f(a,k),k)).
The set A2 of vertices of H×GH of the form ((o,k),(k∗o,h)), for (k,h)∈K2, meets all the orbits of H×GH. Observe also that one has μ((o,k),(k∗o,h))=(o,kh). The arrows (eo,k), (ck,h), (eo,kh) in H join respectively (o,k), (k∗o,h), (o,kh) to (o,k), (o,h) and (o,kh). Let Z2 denote the set of sequences of the form (((o,k),1),((k∗o,h),1),((o,kh),−1)) in Ω(Γ); for such an element z of Z2, put f(z)=((eo,k),(ck,h),(eo,kh)).
By Prop. 4 of II, p. 202, the set Z=Z1∪Z2 and the family (f(z))z∈Z is a complementary equipment.
Let k∈K and let a∈Ak. The element C((a,k),1) of the group Go∗F(K) defined by formula (2) of II, p. 208 is equal to
Let k and h∈K be given. One verifies that the element
C(((o,k),1),((k∗o,h),1),((o,kh),−1))
of the group Go∗F(K) defined by formula (2) of II, p. 208 is equal to
[k][h](ch−1h∗(ck−1)ckh)[kh]−1(5)
The elements r3′(e,a) given by the relations (R3′) for k=e are all equal to [e]ce−1, an element of the group Go∗F(K) which one obtains by applying the relation (R3′′) to k=h=e. Taking account of relations (3), (4), and (5), the proposition therefore follows from II, p. 208, Prop. 5.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.