Bourbaki

Proposition 1

Tag 01YH, permanent. Cite it as [Bourbaki, Tag 01YH].

Topologie algébrique, chapter III, § 3. Groupoïde de Poincaré

Let X be a topological space, let x,y,z,ux,y,z,u be points of X, and let γ1∈ϖx,y(X),γ2∈ϖy,z(X),γ3∈ϖz,u(X)\gamma_1\in \varpi_{x,y}(X),\gamma_2\in \varpi_{y,z}(X),\gamma_3\in \varpi_{z,u}(X) be path classes. One has

εxγ1=γ1εy=γ1(1) \varepsilon_x\gamma_1=\gamma_1\varepsilon_y=\gamma_1 \tag{1}
γ1γ‾1=εx,γ‾1γ1=εy(2) \gamma_1\overline{\gamma}_1=\varepsilon_x,\overline{\gamma}_1\gamma_1=\varepsilon_y \tag{2}
(γ1γ2)γ3=γ1(γ2γ3)(3) (\gamma_1\gamma_2)\gamma_3=\gamma_1(\gamma_2\gamma_3) \tag{3}

Let c1∈Λx,y(X),c2∈Λy,z(X),c3∈Λz,u(X)c_1\in \Lambda_{x,y}(X),c_2\in \Lambda_{y,z}(X),c_3\in \Lambda_{z,u}(X) be representatives of γ1,γ2\gamma_1,\gamma_2 and γ3\gamma_3 respectively. Let φ:I→I\varphi :\mathbf{I}\rightarrow \mathbf{I} be the function defined by

t/2t/2 for 0⩽t⩽1/20\leqslant t\leqslant 1/2,

(4) φ(t)=t−1/4\varphi (t) =t-1/4 for 1/2⩽t⩽3/41/2\leqslant t\leqslant 3/4,

2t−12t-1 for 3/4⩽t⩽13/4\leqslant t\leqslant 1.

The function φ\varphi is affine on each of the three intervals [0,1/2][0,1/2], [1/2,3/4][1/2,3/4] and [3/4,1][3/4,1]; it is therefore continuous. One has φ(0)=0\varphi (0) = 0 and φ(1)=1\varphi (1) = 1. It follows from formula (1) of III, p. 256 defining the juxtaposition of paths that

c1∗(c2∗c3)=((c1∗c2)∗c3)∘φ c_1*(c_2*c_3) = ((c_1*c_2)*c_3)\circ \varphi

By the example of III, p. 289, the paths c1∗(c2∗c3)c_1*(c_2*c_3) and (c1∗c2)∗c3(c_1*c_2)*c_3 are strictly homotopic, whence equality (3).

Analogously, the function ψ:I→I\psi :\mathbf{I}\rightarrow \mathbf{I} defined by

2t2t for 0⩽t⩽1/20\leqslant t\leqslant 1/2,

ψ(t)=(5) \psi (t) = \tag{5}

1 for 1/2⩽t⩽11/2\leqslant t\leqslant 1

is continuous and satisfies ψ(0)=0,ψ(1)=1\psi (0) = 0,\psi (1) = 1. The equality γ1εy=γ1\gamma_1\varepsilon_y=\gamma_1 then follows from the fact that

c1∗ey=c1∘ψ c_1*e_y=c_1\circ \psi

and the equality εxγ1=γ1\varepsilon_x\gamma_1=\gamma_1 is proved analogously, whence (1).

The mapping σ:I×I→X\sigma :\mathbf{I}\times \mathbf{I}\rightarrow X defined by

c1(2ts)c_1(2ts) for 0⩽t⩽1/20\leqslant t\leqslant 1/2,

σ(t,s)=(6) \sigma (t, s) = \tag{6}

c1(2(1−t)s)c_1(2(1-t)s) for 1/2⩽t⩽11/2\leqslant t\leqslant 1

is continuous; it is a strict homotopy joining the path exe_x to the path c1∗c1‾c_1*\overline{c_1}, whence the first equality in (2). The second results from the first and from the fact that, for every path cc, one has c=c‾‾c=\overline{\overline{c}}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.