Let X and Y be topological spaces, f0 and f1 continuous mappings of X into Y, and let σ:X×I→ Y be a homotopy joining f0 to f1. Let x be a point of X; put y0=f0(x), y1=f1(x), and denote by δ∈ϖy0,y1(Y) the class of the path d defined by d(t)=σ(x,t) for t∈I. For every γ∈π1(X,x), one has (f1)∗(γ)= δ−1((f0)∗(γ))δ.
Let c be a loop in X at x and let γ be its strict homotopy class. Put γ0=(f0)∗(γ) and γ1=(f1)∗(γ); these are the strict homotopy classes of f0∘c and f1∘c. For (t,s)∈I×I, put φ(t,s)=σ(c(t),s). For every t∈I, one has φ(t,0)=(f0∘c)(t),φ(t,1)=(f1∘c)(t) and φ(0,t)=φ(1,t)=d(t). The relation γ0δ=δγ1 therefore follows from the following lemma.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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