Bourbaki

Proposition 4

Tag 01YU, permanent. Cite it as [Bourbaki, Tag 01YU].

Topologie algébrique, chapter III, § 3. Groupoïde de Poincaré

Let X be the product space of a family (Xj)j∈J(X_j)_{j\in J} of topological spaces. The morphism of the groupoid ϖ(X)\varpi (X) into the product of the groupoids ϖ(Xj)\varpi (X_j), for j∈Jj\in J, defined by the family of morphisms (ϖ(\varpi(prj_j))j∈J_{j\in J} is an isomorphism.

Let φ\varphi denote this morphism of groupoids. The mapping deduced from it by passing to the vertices is the identity mapping X→∏jXjX\rightarrow \prod_jX_j. Let x=(xj)x= (x_j) and y=(yj)y= (y_j) be two points of X. Let φx,y\varphi_{x,y} denote the mapping of ϖx,y(X)\varpi_{x,y}(X) into ∏jϖxj,yj(Xj)\prod_j\varpi_{x_j,y_j}(X_j) deduced from φ\varphi. If for every j∈J,cj:I→j\in J,c_j:\mathbf{I}\rightarrow XjX_j is a path joining xjx_j to yjy_j, the mapping t↦(cj(t))t\mapsto (c_j(t)) is a path in X joining xx to yy (TG, I, p. 25, prop. 1). This proves that φx,y\varphi_{x,y} is surjective. Let cc and dd be two paths in X joining xx to yy. Suppose that for every j∈Jj\in J there exists a strict homotopy σj:I×I→Xj\sigma_j:\mathbf{I}\times \mathbf{I}\rightarrow X_j joining prj∘c_j\circ c to prj∘d_j\circ d. Then the mapping (t,s)↦(σj(t,s))(t, s)\mapsto (\sigma_j(t, s)) of I×I\mathbf{I}\times \mathbf{I} into X is a strict homotopy joining cc to d(d(loc. cit.). This proves that φx,y\varphi_{x,y} is injective.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.