Bourbaki

Corollary 3

Tag 021T, permanent. Cite it as [Bourbaki, Tag 021T].

Topologie algébrique, chapter IV, § 3. Groupes de Poincaré des groupes topologiques

Let G be a simply connected topological group and let V be a connected neighbourhood of the identity element of G. One defines a presentation of G by taking as generator set the set V and as set r\mathbf{r} of relations the family of the xyz−1xyz^{-1}, where (x,y,z)(x, y, z) runs through the triples of elements of V such that xy=zxy=z.

Let F(V,r)F(V,\mathbf{r}) be the quotient group of the free group F(V) by the smallest normal subgroup containing the elements xyz−1xyz^{-1}, where (x,y,z)∈V×(x, y, z)\in V\times V×VV\times V and xy=zxy=z (A, I, p. 86). Let us denote by f:V→F(V,r)f: V\rightarrow F(V,\mathbf{r}) and g:F(V,r)→Gg: F(V,\mathbf{r})\rightarrow G the canonical mappings. By construction, the mapping ff is a local homomorphism of G into F(V,r)F(V,\mathbf{r}). By corollary 1, there exists a unique group homomorphism f‾:G→F(V,r)\overline{f}: G\rightarrow F(V,\mathbf{r}) extending ff. Since the group F(V,r)F(V,\mathbf{r}) is generated by f(V)f(V), the homomorphism f‾\overline{f} is surjective. For x∈Vx\in V, one has g(f‾(x))=g(f(x))=xg(\overline{f}(x)) =g(f(x)) =x; since V generates G,g∘f‾=,g\circ \overline{f}= IdG_G, which proves that f‾\overline{f} is injective. It is therefore an isomorphism.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.