Bourbaki

Example 2

Tag 021W, permanent. Cite it as [Bourbaki, Tag 021W].

Topologie algébrique, chapter IV, § 3. Groupes de Poincaré des groupes topologiques

Let X be a topological space and xx a point of X. Endowed with the juxtaposition of loops at xx, the pointed space (Ωx(X),ex)(\Omega_x(X), e_x) is a Hopf space. In fact, first one has ex∗ex=exe_x*e_x=e_x. On the other hand, let ψ:I→I\psi :\mathbf{I}\rightarrow \mathbf{I} be the function defined by ψ(t)=2t\psi (t) = 2t for 0⩽t⩽120\leqslant t\leqslant \frac{1}{2} and ψ(t)=1\psi (t) = 1 for 12⩽t⩽1\frac{1}{2}\leqslant t\leqslant 1 (cf. III, p. 291), and let σ:I×I→I\sigma :\mathbf{I}\times \mathbf{I}\rightarrow \mathbf{I} be a strict homotopy connecting ψ\psi with IdI(_{\mathbf{I}}(III, p. 289, example). Then, for every loop c∈Ωx(X)c\in \Omega_x(X), the mapping c∘σ:I×I→Xc\circ \sigma :\mathbf{I}\times \mathbf{I}\rightarrow X is a strict homotopy connecting c∗exc*e_x with cc in Ωx(X)\Omega_x(X).

Let τ\tau be the mapping Ωx(X)×I→Ωx(X)\Omega_x(X)\times \mathbf{I}\rightarrow \Omega_x(X) defined by τ(c,s)(t)=\tau (c, s)(t) = c∘σ(s,t)c\circ \sigma (s, t). Let us now prove that τ\tau is continuous. By proposition 1 of III, p. 257, it is enough to show that the mapping (c,s,t)↦c(σ(s,t))(c, s, t)\mapsto c(\sigma (s, t)) of Ωx(X)×I×I\Omega_x(X)\times \mathbf{I}\times \mathbf{I} into X is continuous, or again, since I×I\mathbf{I}\times \mathbf{I} is compact, that the mapping c↦c∘σc\mapsto c\circ \sigma of Cc(I;X)\mathscr{C}_c(\mathbf{I}; X) into Cc(I×I;X)\mathscr{C}_c(\mathbf{I}\times \mathbf{I}; X) is continuous. This last assertion then follows from the lemma, I, p. 132, b). Hence the mapping τ\tau is a homotopy connecting the mapping c↦c∗exc\mapsto c*e_x with the identity mapping of Ωx(X)\Omega_x(X). One has τ(ex,s)(t)=x\tau (e_x, s)(t) =x for all s,t∈Is,t\in \mathbf{I}; therefore τ\tau is a homotopy pointed at exe_x. One reasons analogously for the mapping c↦ex∗cc\mapsto e_x*c.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.