Bourbaki

Exercise 22, § 2

Tag 0279, permanent. Cite it as [Bourbaki, Tag 0279].

Spectral Theories, I, p. 159

Bourbaki marks this one as harder than the rest.

Let A be a Banach algebra.

(a) Let S be the set of the bounded sequences of elements of A, with the norm ∥(xn)∥=\|(x_n)\|= sup ∥xn∥\|x_n\|. Let R be the set of the (xn)∈S(x_n)\in S such that ∥xn∥\|x_n\| tends to 0. Then S is a Banach algebra and R is a closed two-sided ideal of S.

Let S′=S/RS'= S/R and φ:S→S′\varphi : S\rightarrow S' be the canonical morphism.

(b) The mapping θ\theta of A into S′S' defined by θ(x)=φ(x,x,x,...)\theta (x) =\varphi (x, x, x, . . .) is an isometric isomorphism of A onto a subalgebra of S′S'. Every left topological divisor of zero in S′S' is a left divisor of zero. In order that x∈Ax\in A be a left topological divisor of zero, it is necessary and sufficient that θ(x)\theta (x) be a left divisor of zero in S′S'.

(c) Suppose that A has a unit element. Prove that there exist a Banach algebra B and an isometric isomorphism of A onto a subalgebra of B such that an element of A is non-invertible if, and only if, its image in B is a left or right divisor of zero. (Use a) and Exercises 19 and 21.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.