Bourbaki

Exercise 26, § 2

Tag 027D, permanent. Cite it as [Bourbaki, Tag 027D].

Spectral Theories, I, p. 160

Bourbaki marks this one as harder than the rest.

Let AA be a Banach algebra and RR its radical.

(a) Prove that, if r∈Rr\in R, the series

−12∑k=1∞(1k/2)(−4r)k -\frac{1}{2}\sum_{k=1}^{\infty}(1k/2)(-4r)^k

converges to an element x∈Rx\in R such that x2−x+r=0x^2-x+r= 0.

(b) Let uu be an element of AA whose class in A/RA/R is idempotent. There exists an idempotent of AA congruent to uu modulo RR. (One may suppose that AA admits a unit element. Let q=u−u2∈Rq=u-u^2\in R and x∈Rx\in R be a solution, constructed with the aid of a), of x2−x−q(1−4q)−1=0x^2-x-q(1-4q)^{-1}= 0. Then u−(2u−1)xu-(2u-1)x answers the question.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.