Bourbaki

Exercise 29, § 2

Tag 027G, permanent. Cite it as [Bourbaki, Tag 027G].

Spectral Theories, I, p. 161

a) Let E be a complex Banach space, f:C→Ef:\mathbf{C}\rightarrow E an entire function and θ↦P(θ)=∑μ=kmcμeμiθ\theta \mapsto P(\theta ) =\sum^m_{\mu=k}c_\mu e^{\mu i\theta} a trigonometric polynomial (ck≠0(c_k\not= 0). It is assumed that ∣P(θ)∣⋅∥f(reiθ)∥⩽Mrα|P(\theta )| \cdot \|f(re^{i\theta})\|\leqslant Mr^{\alpha} for r⩾r0(r\geqslant r_0(M,r0,α,r_0,\alpha being constants ⩾0\geqslant 0). Then ff is a polynomial of degree ⩽α\leqslant \alpha. (Let f(ζ)=f(\zeta ) = ∑ν=0∞aνζν\sum^{\infty}_{\nu=0}a_{\nu}\zeta^{\nu}, and

J(r,p)=r−p∫02πP(θ)f(reiθ)e−(k+p)iθdθ J(r, p) =r^{-p}\int_0^{2\pi}P(\theta )f(re^{i\theta})e^{-(k+p)i\theta}d\theta

Calculate the limit of J(r,p)J(r, p) when r→+∞r\rightarrow +\infty in two different ways for p>α.)p > \alpha .)

b) With the notation of a), if α\alpha is an integer and if, for every θ∈R\theta \in \mathbf{R}, one has

limr→+∞r−α∣P(θ)∣∥f(reiθ)=0_{r\rightarrow+\infty}r^{-\alpha}|P(\theta )| \|f(re^{i\theta}) = 0,

then ff is a polynomial of degree <α< \alpha.

c) Let A be a complex unital Banach algebra and xx an element of A which is quasi-nilpotent. It is assumed that, for a certain integer n>0n >0, and for every θ∈R\theta \in \mathbf{R}, one has

limr→+∞r−n∣_{r\rightarrow+\infty}r^{-n}| cosnθ∣⋅∥(1−reiθx)−1∥=0^n\theta | \cdot \|(1-re^{i\theta}x)^{-1}\|= 0.

Then xn=0x^n= 0. (Use b).)

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.