Bourbaki

Exercise 36, § 2

Tag 027N, permanent. Cite it as [Bourbaki, Tag 027N].

Spectral Theories, I, p. 164

Bourbaki marks this one as harder than the rest.

Let A be the algebra over C\mathbf{C} formed by the restrictions to [0,1][0,1] of rational functions in one variable with complex coefficients. This algebra is a field.

a) We endow A with the topology of convergence in measure (INT, IV, §5, no11^o11). Then the mappings (x,y)↦x+y(x, y)\mapsto x+y and (x,y)↦xy(x, y)\mapsto xy from A×AA\times A into A are continuous, and the mapping x↦x−1x\mapsto x^{-1} from A∗A^* into A is continuous. The topology of A is not locally convex.

b) For n∈N∗n\in \mathbf{N}^*, we define the sequence (wr,n)r∈Z(w_{r,n})_{r\in\mathbf{Z}} by wr,n=(−r+1)n(−r+1)w_{r,n}= (-r+ 1)^{n(-r+1)} if r<0,w0,n=1r <0,w_{0,n}= 1 and wr,n=(r+1)−(r+1)/nw_{r,n}= (r+ 1)^{-(r+1)/n} if r>0r >0. If f∈Af\in A, we put pn(f)=∑rwr,n∣ar∣<+∞p_n(f) =\sum_rw_{r,n}|a_r|<+\infty, where ∑artr\sum a_rt^r is the Laurent expansion of f(t)f(t) at 0. Then the pnp_n are seminorms which define on A a locally convex metrizable topology. The mapping (x,y)↦xy(x, y)\mapsto xy from A×AA\times A into A is continuous. The mapping x↦x−1x\mapsto x^{-1} from A∗A^* into A is not continuous. The algebra A is not complete for this topology.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.