Lemma 1
Tag 027Y, permanent. Cite it as [Bourbaki, Tag 027Y].
Théories spectrales, chapter I, § 3. Algèbres de Banach commutatives
For every proper partial mapping of X into Y, with domain of definition U, let us denote by the mapping of into defined by if and if ; it is continuous.
The mapping is a bijection between the set of proper partial mappings of X into Y and the set of continuous mappings of into such that .
Let be a proper partial mapping of X into Y, and let U be its domain. We shall prove that the mapping is continuous. It is continuous at every point of U, since U is open in . We shall prove that it is also continuous at every point of U; then . Let V be an open neighbourhood of in ; we shall prove that is a neighbourhood of . By definition of the topological space , we may suppose that V is of the form K, where K is a compact subset of Y. Since defines a proper mapping of U into Y, the set is compact in U (TG, I, p. 77, prop. 6), hence in . In particular it is a closed subset of , and is an open subset of , and is therefore a neighbourhood of .
Conversely, let be a continuous mapping such that , and let be its graph. The set U = X is open in X. The correspondence is a proper partial mapping of X into Y (TG, I, p. 77, prop. 7) such that , and it is the only one.
We shall identify the proper partial mappings of X into Y with the continuous mappings of into which map onto . In particular, the proper mappings of X into Y are the proper partial mappings with domain X; they are identified with the continuous mappings of into such that that . If X is compact, these are simply the continuous mappings of X into Y.
Let A be a commutative complex Banach algebra. Recall that is identified with the compact space obtained from by adjoining a point at infinity (I, p. 29, corollaire).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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