Bourbaki

Proposition 12

Tag 028P, permanent. Cite it as [Bourbaki, Tag 028P].

Théories spectrales, chapter I, § 3. Algèbres de Banach commutatives

Let Λ be a set and A a commutative unital Banach algebra. Let x=(xλ)λ∈Λx= (x_{\lambda})_{\lambda\in\Lambda} be a family of elements of A.

a) Suppose that the full subalgebra of A generated by the family xx is dense in A. The mapping of X(A)\mathsf{X}(A) into CΛ\mathbf{C}^{\Lambda} defined by xx is a homeomorphism of X(A)\mathsf{X}(A) onto the joint spectrum SpAΛ(x)^{\Lambda}_A(x) ;

b) Suppose that the unital subalgebra of A generated by the family xx is dense in A. For every c∈CΛc\in \mathbf{C}^{\Lambda}, the following conditions are equivalent :

(i) c∈c\in SpAΛ(x)^{\Lambda}_A(x) ;

(ii) ∣P(c)∣⩽ϱ(P(x))|P(c)|\leqslant \varrho (P(x)) for every polynomial P∈C[(Xλ)λ∈Λ]P\in \mathbf{C}[(X_{\lambda})_{\lambda\in\Lambda}];

(iii) ∣P(c)∣⩽∥P(x)∥|P(c)|\leqslant \|P(x)\| for every polynomial P∈C[(Xλ)λ∈Λ]P\in \mathbf{C}[(X_{\lambda})_{\lambda\in\Lambda}].

a) The mapping of X(A)\mathsf{X}(A) into SpAΛ(x)^{\Lambda}_A(x) defined by the family xx is continuous and surjective. Let χ,χ′∈X(A)\chi ,\chi '\in \mathsf{X}(A) be characters having the same image, that is, such that χ(xλ)=χ′(xλ)\chi (x_{\lambda}) =\chi '(x_{\lambda}) for every λ∈Λ\lambda \in \Lambda. The characters χ\chi and χ′\chi ' coincide on elements of the form P(x)Q(x)−1P(x)Q(x)^{-1}, where P∈C[(Xλ)]P\in \mathbf{C}[(X_{\lambda})], Q∈C[(Xλ)]Q\in \mathbf{C}[(X_{\lambda})] and Q(x)Q(x) is invertible in A, that is, on the full subalgebra of A generated by the elements xλx_{\lambda} (lemma 2 of I, p. 6). Since χ\chi and χ′\chi ' are continuous (Theorem 1 of I, p. 29), they are therefore equal on A. This proves that X(h)\mathsf{X}(h) is a continuous bijection of X(A)\mathsf{X}(A) onto SpAΛ(x)^{\Lambda}_A(x), and hence is a homeomorphism since X(A)\mathsf{X}(A) is compact.

b) Let us show that (i) implies (ii): if c=(cλ)λ∈Λ∈c= (c_{\lambda})_{\lambda\in\Lambda}\in SpAΛ(x)^{\Lambda}_A(x), there exists χ∈X(A)\chi \in \mathsf{X}(A) such that cλ=χ(xλ)c_{\lambda}=\chi (x_{\lambda}) for every λ\lambda. For every P∈C[(Xλ)]P\in \mathbf{C}[(X_{\lambda})], we therefore have ∣P(c)∣=∣P((χ(xλ))λ∈Λ)∣=∣χ(P(x))∣⩽ϱ(P(x))|P(c)|=|P((\chi (x_{\lambda}))_{\lambda\in\Lambda})|=|\chi (P(x))|\leqslant \varrho (P(x)).

Assertion (ii) implies (iii) by reason of the inequality ϱ(x)⩽∥x∥\varrho (x)\leqslant \|x\|, valid for every x∈Ax\in A by definition of the spectral radius.

Finally let us show that (iii) implies (i). Let c=(cλ)λ∈Λ∈CΛc= (c_{\lambda})_{\lambda\in\Lambda}\in \mathbf{C}^{\Lambda} be such that

∣P(c)∣⩽∥P(x)∥(2) |P(c)|\leqslant \|P(x)\| \tag{2}

for every P ∈C[(Xλ)]\in \mathbf{C}[(X_{\lambda})]. Let A′A' be the unital subalgebra of A generated by the family xx; its elements are of the form P(x)P(x) for P∈C[(Xλ)]P\in \mathbf{C}[(X_{\lambda})]. The majorisation (2) implies that the condition P(x)=0P(x) = 0 entails P(c)=0P(c) = 0. There therefore exists a morphism of unital algebras ξ\xi from A′A' into C\mathbf{C} such that ξ(xλ)=cλ\xi (x_{\lambda}) =c_{\lambda} for every λ∈Λ\lambda \in \Lambda. By (2), the morphism ξ\xi is continuous. It therefore extends by continuity to a character χ\chi of A′‾=A\overline{A'}= A, which satisfies c=(χ(xλ))λ∈Λ∈c= (\chi (x_{\lambda}))_{\lambda\in\Lambda}\in SpAΛ(x)^{\Lambda}_A(x). This completes the proof.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.