Lemma 5
Tag 028V, permanent. Cite it as [Bourbaki, Tag 028V].
Théories spectrales, chapter I, § 3. Algèbres de Banach commutatives
Let K be a compact subset of . We denote by the union of K and of the connected components of K which are relatively compact. Then the set is compact.
Since K is compact, there exists a real number such that K is contained in the open disk D with center 0 and radius . Then K contains D. Since the space D is connected (being homeomorphic to , it is contained in a connected component U of K. Every other connected component of K is contained in D, hence is bounded. The connected component U is therefore the unique unbounded connected component of K, that is, . Since U is open and contains the complement of the disk D, the set is compact.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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