Let E be a complex vector space and u a semilinear involution on E. Let x∈E; put
x1=21(x+u(x)),x2=2i1(x−u(x))
The pair (x1,x2) is the unique element of Eu×Eu such that x=x1+ix2.
The elements x1 and x2 satisfy x1+ix2=x and belong to Eu since u(u(x))=x. Conversely, if y1 and y2 in Eu satisfy x=y1+iy2, it follows that u(x)=u(y1)+u(iy2)=y1−iy2, hence
y1=21(x+u(x))=x1,iy2=21(x−u(x))=ix2
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.