Bourbaki

Lemma 1

Tag 02CI, permanent. Cite it as [Bourbaki, Tag 02CI].

Théories spectrales, chapter I, § 6. Algèbres stellaires

Let E be a complex vector space and uu a semilinear involution on E. Let x∈Ex\in E; put

x1=12(x+u(x)),x2=12i(x−u(x)) x_1=\frac{1}{2}(x+u(x)),x_2=\frac{1}{2i}(x-u(x))

The pair (x1,x2)(x_1, x_2) is the unique element of Eu×EuE^u\times E^u such that x=x1+ix2x=x_1+ix_2.

The elements x1x_1 and x2x_2 satisfy x1+ix2=xx_1+ix_2=x and belong to EuE^u since u(u(x))=xu(u(x)) =x. Conversely, if y1y_1 and y2y_2 in EuE^u satisfy x=y1+iy2x=y_1+iy_2, it follows that u(x)=u(y1)+u(iy2)=y1−iy2u(x) =u(y_1) +u(iy_2) =y_1-iy_2, hence

y1=12(x+u(x))=x1,iy2=12(x−u(x))=ix2 y_1=\frac{1}{2}(x+u(x)) =x_1,iy_2=\frac{1}{2}(x-u(x)) =ix_2

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.