Let A be an involutive Banach algebra, let B be a stellar algebra, and let π be a morphism of involutive algebras from A into B. One has ∥π(x)∥⩽∥x∥ for all x∈A, and in particular π is continuous.
For every x∈A, one has SpB′(π(x))⊂ SpA′(x), therefore ϱ(π(x))⩽ϱ(x)⩽∥x∥. Since π(x∗x)∈Bh, one has ∥π(x∗x)∥=ϱ(π(x∗x)) (formula (2)), therefore
∥π(x)∥2=∥π(x∗x)∥=ϱ(π(x∗x))⩽∥x∗x∥=∥x∥2
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.