Bourbaki

Proposition 13

Tag 02EA, permanent. Cite it as [Bourbaki, Tag 02EA].

Théories spectrales, chapter I, § 6. Algèbres stellaires

We have the following properties:

a) For every f∈C′f\in \mathscr{C}'(SpA′(x)'_A(x)), we have SpA′(f(x))=f'_A(f(x)) =f(SpA′(x)'_A(x)) ;

b) For every f∈C′f\in \mathscr{C}'(SpA′(x)'_A(x)) and for every g∈C′g\in \mathscr{C}'(SpA′(f(x))'_A(f(x))), we have (g∘f)(x)=g(f(x))(g\circ f)(x) =g(f(x)) ;

c) Let A′A' be a stellar algebra and let π\pi be a morphism from A into A′A'; then π(x)\pi (x) is normal in A′A', we have SpA′′(π(x))⊂'_{A'}(\pi (x))\subset SpA′(x)'_A(x) and π(f(x))=f(π(x))\pi (f(x)) =f(\pi (x)) for every f∈C′f\in \mathscr{C}'(SpA′(x)'_A(x));

d) If A is commutative, and if f∈C′f\in \mathscr{C}'(SpA′(x)'_A(x)), then GA′(f(x))=\mathscr{G}'_A(f(x)) = f∘GA′(x)f\circ \mathscr{G}'_A(x).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.