Bourbaki

Lemma 13

Tag 02EK, permanent. Cite it as [Bourbaki, Tag 02EK].

Théories spectrales, chapter I, § 6. Algèbres stellaires

Let A be a unital stellar algebra. Every element of A is a sum of unitary elements.

By the lemmaLet xx be a hermitian element of12, c), one has 1−14Ax1-\frac{1}{4}Ax. Suppose first that2∈A+_2\in A_+. Let y=12x+i√∥1x−∥⩽14‾x22y=\frac{1}{2}x+i\surd\|1x-\|\leqslant_{1\overline{4}}x2_2..

One has y∗=12x−i√1−14x2‾y^*=\frac{1}{2}x-i\surd\overline{1 -\frac{1}{4}x^2}, hence yy∗=1yy^*= 1 and x=y+y∗x=y+y^* is a sum of two unitary elements. In the general case, let kk be an integer such that ∥1kx∥⩽2\|\frac{1}{k}x\|\leqslant 2 ; the element xx is then a sum of 2k2k unitary elements. By Lemma 2 of I, p. 96, the lemma follows.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5-6-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.