Bourbaki

Exercise 6, § 6

Tag 02F9, permanent. Cite it as [Bourbaki, Tag 02F9].

Spectral Theories, I, p. 180

Bourbaki marks this one as harder than the rest.

Let AA be a commutative unital involutive Banach algebra all of whose characters are hermitian. Suppose that, for every hermitian non-invertible element x∈Ax\in A, one has ∥(x−λ)−1∥=o(I(λ)−2)\|(x-\lambda )^{-1}\|=o(\mathscr{I}(\lambda )^{-2}) when λ\lambda tends to 0 with I(λ)≠0\mathscr{I}(\lambda )\not= 0. Then every closed ideal I of A is intersection of maximal ideals. (Let φ:A⟶A/I\varphi : A\longrightarrow A/I be the canonical morphism. Let x∈Ax\in A be such that φ(x)\varphi (x) is in the radical of A/IA/I. It is necessary to prove that φ(x)=0\varphi (x) = 0. Reduce to the case where xx is hermitian. Use then Exercise 29 of I, p. 161).

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.