Bourbaki

Exercise 7, § 6

Tag 02FA, permanent. Cite it as [Bourbaki, Tag 02FA].

Spectral Theories, I, p. 181

Let AA be a commutative unital involutive Banach algebra. In order that every character of AA be hermitian, it is necessary and sufficient that 1+xx∗1+xx^* be invertible for every x∈Ax\in A. (If every character of AA is hermitian, G(1+xx∗)\mathscr{G}(1+xx^*) is everywhere >0>0 on X(A)\mathsf{X}(A). If a character χ\chi of AA is non-hermitian, there exists a hermitian x∈Ax\in A such that χ(x)=i\chi (x) =i, whence χ(1+xx∗)=0\chi (1+xx^*) = 0 and 1+xx∗1+xx^* is not invertible.)

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.