Bourbaki

Exercise 32, § 6

Tag 02FZ, permanent. Cite it as [Bourbaki, Tag 02FZ].

Spectral Theories, I, p. 186

Let G be a group. We say that G has the Powers property if, for every n∈Nn\in \mathbf{N} and every finite subset F of G−{e}-\{e\}, there exists a partition of G into two subsets A and B and a family (gi)1⩽i⩽n(g_i)_{1\leqslant i\leqslant n} of elements of G such that

(i) for every g∈Fg\in F, the sets A and gAgA are disjoint ;

(ii) for all distinct integers jj and kk between 1 and nn, the sets gjBg_jB and gkBg_kB are disjoint.

Let G be a group possessing the Powers property. Let I be a nonzero closed two-sided ideal of the reduced stellar algebra Stellr(G)_r(G) (exercise 25). Let π:C[G]→\pi :\mathbf{C}[G]\rightarrow Stellr(G)_r(G) be the canonical representation.

a) There exists a family (λg)g∈G−{e}(\lambda_g)_{g\in G-\{e\}} in C\mathbf{C} such that

x=∑g∈G−{e}λgπ(g) x=\sum_{g\in G-\{e\}}\lambda_g\pi (g)

is a hermitian element of Stellr(G)_r(G) such that y=1+xy= 1 +x belongs to I. b) Let ε>0\varepsilon >0 be such that ε<1\varepsilon <1. There exists a finite subset F of G−{e}-\{e\} and an integer n⩾1n\geqslant 1 such that the element

x′=∑g∈Fλgπ(g) x'=\sum_{g\in F}\lambda_g\pi (g)
√\surd

satisfies ∥x′−x∥<ε\|x'-x\|< \varepsilon and ∥x′∥<2n(1−ε)\|x'\|<_2^n(1-\varepsilon ).

c) Let G=A∪BG = A\cup B and (gi)1⩽i⩽n(g_i)_{1\leqslant i\leqslant n} satisfying the conditions of the Powers property for the finite subset F and the integer nn. Put

′' 1 n′−1n'-1

yy = ∑π(gi)xπ(gi)\sum\pi (g_i)x\pi (g_i).

n n
i=1i=1

We have ∥y′∥<1−ε\|y'\|<1-\varepsilon. (Let pip_i be the orthogonal projection of ℓ2(G)\ell^2(G) onto ℓ2(giB)\ell^2(g_iB) ; verify that

(1−pi)π(gi)x′π(gi−1)(1−pi)=0 (1-p_i)\pi (g_i)x'\pi (g_i^{-1})(1-p_i) = 0

for 1⩽i⩽n1\leqslant i\leqslant n, and deduce that

1+y′=1+1n∑npiπ(gi)x′π(gi−1)+(1n∑npiπ(gi)x′π(gi−1)(1−pi))∗ 1 +y'= 1 +\frac{1}{n}\sum^np_i\pi (g_i)x'\pi (g_i^{-1}) +(\frac{1}{n}\sum^np_i\pi (g_i)x'\pi (g_i^{-1})(1-p_i))^*
i=1i=1i=1i=1

then note that the endomorphisms piπ(gi)x′π(gi−1)p_i\pi (g_i)x'\pi (g_i^{-1}) have pairwise orthogonal images in order to estimate their norms.)

d) The ideal I contains the element

1 n−1^n-_1

1 + ∑π(gi)xπ(gi)\sum\pi (g_i)x\pi (g_i),

n n
i=1i=1

and this element is invertible. Consequently, the stellar algebra Stellr(G)_r(G) contains no nonzero closed two-sided ideal distinct from {0}\{0\} and Stellr(G)_r(G).

e) Let G be a noncommutative free group. Then G has the Powers property.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.