Spectral Theories, I, p. 194
Bourbaki marks this one as harder than the rest.
Let X be a compact topological space and B a unital Banach subalgebra of C(X) (for the induced norm). Every element x of X defines a character χx of B. If x,x′ are in X, we write x∼x′ when ∥χx−χx′∥=2. a) Let x and x′ be in X. If there exists a sequence (fn) of elements of B such that ∥fn∥⩽1, that ∣fn(x)∣ tends to 1 and that lim infn→∞∣fn(x)−fn(x′)∣>0, then one does not have x∼x′. (One may suppose that fn(x) tends to 1. Consider gn=(fn−λn)(1−λnfn)−1, where (λn) is a sequence of numbers of [0,1[ tending to 1. One has ∥gn∥⩽1. If the sequence (λn) is suitably chosen, gn(x) tends to 1 and gn(x′) tends to −1.)
b) Let R be the set of real parts of the elements of B. If x∼x′, there exists c∈]0,1[ such that f(x)⩾cf(x′) and f(x′)⩾cf(x) for every f⩾0 in R. (It suffices to obtain the first condition; if it is not true, there exists a sequence (fn) in R with fn⩾0,fn(x′)=1,fn(x) tending to 0; let gn∈B with R(gn)=fn. Then e−gn∈B,∥e−gn∥⩽1,∣e−gn(x′)∣=1/e,∣e−gn(x)∣ tends to 1, which contradicts a).)
c) There exist positive measures α and β on X such that f(x)−cf(x′)=α(f) and f(x′)−cf(x)=β(f) for f∈R. Setting μx=(1−c2)−1(cβ+α), μx′=(1−c2)−1(cα+β), one has μx(f)=f(x) and μx′(f)=f(x′) for every f∈B, and cμx⩽μx′,cμx′⩽μx.
d) Suppose again that x∼x′. Prove that if μ is a positive measure on X such that μ(f)=f(x) for every f∈B, there exists a positive measure μ′ on X such that μ′(f)=f(x′) for every f∈B and cμ⩽μ′ for a c∈]0,1[. (With the notation of c), set μ′=μx′−cμx+cμ.)
e) The relation x∼x′ is an equivalence relation in X. (Use d).)
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