Bourbaki

Exercise 9, § 2

Tag 02MX, permanent. Cite it as [Bourbaki, Tag 02MX].

Spectral Theories, II, p. 306

a) Let a=(an)n⩾0\boldsymbol{a}= (a_n)_{n\geqslant 0} be a sequence of integers >1>1. We endow Z\mathbf{Z} with the structure of a topological ring for which the subsets Za0a1⋯an\mathbf{Z}a_0a_1\cdots a_n, where n⩾0n\geqslant 0, form a fundamental system of neighbourhoods of 0. We denote by Δa\Delta_{\boldsymbol{a}} the completion of this ring. It is compact, metrizable and totally disconnected. If pp is a prime number, and if ai=pa_i=p for all ii, we have Δa=Zp\Delta_{\boldsymbol{a}}=\mathbf{Z}_p.

b) We denote by Z(a∞)\mathbf{Z}(\boldsymbol{a}^{\infty}) the multiplicative group of complex numbers of the form exp(2iπl/(a0a1⋯ar)i\pi l/(a_0a_1\cdots a_r)) where l∈Zl\in \mathbf{Z} and r∈Nr\in \mathbf{N}, endowed with the discrete topology. Then χ↦χ(1)\chi \mapsto \chi (1) is an isomorphism of Δ^a\widehat{\Delta}_{\boldsymbol{a}} onto Z(a∞)\mathbf{Z}(\boldsymbol{a}^{\infty}).

c) Let B be the subgroup of R×Δa\mathbf{R}\times \Delta_{\boldsymbol{a}} formed by the (n,n)(n, n) for n∈Zn\in \mathbf{Z}; it is discrete. We put Σa=(R×Δa)/B\Sigma_{\boldsymbol{a}}= (\mathbf{R}\times \Delta_{\boldsymbol{a}})/B. It is a compact metrizable connected group. (Observe that the canonical image of R\mathbf{R} in Σa\Sigma_{\boldsymbol{a}} is dense, and use lemma 1 of II, p. 244.)

d) Let Γa\Gamma_{\boldsymbol{a}} be the additive subgroup of the discrete group Q\mathbf{Q} formed by the rational numbers of the form l/(a0a1⋯ar)l/(a_0a_1\cdots a_r) where l∈Zl\in \mathbf{Z} and r∈Nr\in \mathbf{N}. If χ∈Σ^a\chi \in \widehat{\Sigma}_{\boldsymbol{a}}, then χ\chi defines a unitary character of R×Δa\mathbf{R}\times \Delta_{\boldsymbol{a}}, hence a unitary character of R\mathbf{R} of the form x↦x\mapsto exp(2iπαχxi\pi \alpha_{\chi}x) where αχ∈R\alpha_{\chi}\in \mathbf{R}. Then χ↦αχ\chi \mapsto \alpha_{\chi} is an isomorphism of Σ^a\widehat{\Sigma}_{\boldsymbol{a}} onto Γa\Gamma_{\boldsymbol{a}}.

e) Now prove that Q^\widehat{\mathbf{Q}} is canonically isomorphic to Σa\Sigma_{\boldsymbol{a}}, where the sequence a\boldsymbol{a} is defined by an=n+2a_n=n+ 2 for all n⩾0n\geqslant 0.

f) Let Rd\mathbf{R}_d be the group R\mathbf{R} endowed with the discrete topology. Now prove that R^d\widehat{\mathbf{R}}_d is isomorphic to (Σ^a)c(\widehat{\Sigma}_{\boldsymbol{a}})^{\mathfrak{c}} where an=n+2a_n=n+ 2 and where c\mathfrak{c} is the power of the continuum. (Consider a basis of R\mathbf{R} as a Q\mathbf{Q}-vector space.)

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.