Bourbaki

Exercise 14, § 2

Tag 02N2, permanent. Cite it as [Bourbaki, Tag 02N2].

Spectral Theories, II, p. 308

Bourbaki marks this one as harder than the rest.

(a) Suppose that every neighbourhood of ee in G contains an element of infinite order. There exists a compact metrizable perfect totally disconnected subset P of G which is a Kronecker set (exercise 15 of II, p. 265), and a nonzero diffuse measure concentrated on P. (Reduce to the case where G is metrizable by using exercise 3, c). Then imitate the construction of TG, IX, p. 64, lemma 3, and use at the same time part e) of exercise 15 of II, p. 265.)

(b) If G=(Z/qZ)NG = (\mathbf{Z}/q\mathbf{Z})^{\mathbf{N}}, there exists a compact perfect totally disconnected subset P of G which is of type KqK_q, and a nonzero diffuse measure concentrated on P.

(c) Suppose G is not discrete. There exists an element τ\tau of M1(G)\mathscr{M}^1(G) such that ∥F(τ)∥∞<ϱ(τ)\|\mathscr{F}(\tau )\|_{\infty}< \varrho (\tau ), where ϱ(τ)\varrho (\tau ) is the spectral radius in M1(G)\mathscr{M}^1(G). There exists a noninvertible element τ′\tau ' of M1(G)\mathscr{M}^1(G) such that F(τ′)⩾1\mathscr{F}(\tau ')\geqslant 1 everywhere on G^\widehat{G}. There exists a nonhermitian character of M1(G)\mathscr{M}^1(G). (Use a), b), exercise 3, c), and part f) of exercise 15 of II, p. 265.)

(d) Deduce from c) that G^\widehat{G}, which is open in X(M1(G))\mathsf{X}(\mathscr{M}^1(G)), is not dense in X(M1(G))\mathsf{X}(\mathscr{M}^1(G)).

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.