Bourbaki

Exercise 4, § 1

Tag 02PM, permanent. Cite it as [Bourbaki, Tag 02PM].

Spectral Theories, III, p. 105

Bourbaki marks this one as harder than the rest.

We keep the notations of the preceding exercise.

a) Let v∈Lc(E)v\in \mathscr{L}^c(E). The radius of convergence of the formal series det(1 −tv-tv) is infinite.

b) Let (vn)n∈N(v_n)_{n\in\mathbf{N}} be a sequence in Lc(E)\mathscr{L}^c(E) converging to v∈Lc(E)v\in \mathscr{L}^c(E). The sequence of formal series det(1 −tvn-tv_n) converges to det(1 −tv-tv) for the topology of simple convergence of the coefficients of formal series.

c) Let v∈Lc(E)v\in \mathscr{L}^c(E). For every extension L of K and every x∈Lx\in L, we denote by det(1−- xvxv) the value at xx of the formal series det(1−tv-tv), which is well defined according to a). We have det(1 +u+u) det(1 +v+v) == det(1 +u+v+u∘v+u+v+u\circ v).

d) Let J be a set and F=C0(J)F =\mathscr{C}_0(J). For all u∈Lc(E;F)u\in \mathscr{L}^c(E; F) and v∈v\in Lc(F;E)\mathscr{L}^c(F; E), we have det(1 −tu∘v-tu\circ v) == det(1 −tv∘u-tv\circ u) as formal series. e) Let v∈Lc(E)v\in \mathscr{L}^c(E). We denote by Tr(vv) the opposite of the coefficient of tt in det(1−tu-tu). If K is of characteristic zero, then

det(1 −tu-tu) == exp(−∑(-\sum Tr(mummu^m)tm)t^m)

m⩾1m\geqslant 1

as formal series.

Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-6. Not checked by a person.