Proposition 2
Tag 02RK, permanent. Cite it as [Bourbaki, Tag 02RK].
Théories spectrales, chapter III, § 3. Endomorphismes de Fredholm et endomorphismes de Riesz
Let E and F be separated locally convex spaces and let be an element of . The following properties are equivalent:
(i) The mapping is a mapping of Fredholm;
(ii) The mapping is a strict morphism, its kernel is of finite dimension, its image is closed and of finite codimension in F ;
(iii) There exist closed vector subspaces of finite codimension of E and of F such that defines by passing to the subspaces an isomorphism of onto ;
(iv) There exist decompositions into topological direct sum and such that and are of finite dimension, that vanishes on and defines by passing to the subspaces an isomorphism of onto .
(i) (iii): Let be a quasi-inverse of the kernel of and that of . Since the linear mappings and are continuous and of finite rank, and are closed vector subspaces of finite codimension of E and F respectively. Let . We have
whence . Therefore ; analogously, . The continuous linear mappings and induced by and are then isomorphisms inverse to one another, since and (resp. and ) coincide on (resp. on ).
(iii) (ii): Let and satisfy the hypothesis of (iii). We have Ker() and Im(), hence Ker() is finite-dimensional and Im() is closed and of finite codimension in F. It follows from Prop. 1 of III, p. 39 that the mapping is a strict morphism.
(ii) (iv): Suppose condition (ii) satisfied. The closed vector subspace Ker() of E is finite-dimensional, and there exists a vector subspace of E which is a topological supplement of (TVS, II, p. 27, Cor. 2). The vector subspace Im() of F is closed and of finite codimension, and admits a topological supplement in F. By Prop. 1 of III, p. 39, the mapping is a strict morphism, hence induces an isomorphism of onto .
(iv) (i): Under the hypotheses of (iv), the linear mapping of F into E which coincides with on and is zero on is a quasi-inverse of .
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
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