Bourbaki

Proposition 2

Tag 02RK, permanent. Cite it as [Bourbaki, Tag 02RK].

Théories spectrales, chapter III, § 3. Endomorphismes de Fredholm et endomorphismes de Riesz

Let E and F be separated locally convex spaces and let uu be an element of L(E;F)\mathscr{L}(E; F). The following properties are equivalent:

(i) The mapping uu is a mapping of Fredholm;

(ii) The mapping uu is a strict morphism, its kernel is of finite dimension, its image is closed and of finite codimension in F ;

(iii) There exist closed vector subspaces of finite codimension E1E_1 of E and F1F_1 of F such that uu defines by passing to the subspaces an isomorphism of E1E_1 onto F1F_1;

(iv) There exist decompositions into topological direct sum E=E1⊕E2E = E_1\oplus E_2 and F=F1⊕F2F = F_1\oplus F_2 such that E2E_2 and F2F_2 are of finite dimension, that uu vanishes on E2E_2 and defines by passing to the subspaces an isomorphism of E1E_1 onto F1F_1.

(i) =⇒=\Rightarrow (iii): Let vv be a quasi-inverse of u,E1u, E_1 the kernel of 1E−v∘u1_E-v\circ u and F1F_1 that of 1F−u∘v1_F-u\circ v. Since the linear mappings 1E−v∘u1_E-v\circ u and 1F−u∘v1_F-u\circ v are continuous and of finite rank, E1E_1 and F1F_1 are closed vector subspaces of finite codimension of E and F respectively. Let x∈E1x\in E_1. We have

(1F−u∘v)(u(x))=u((1E−v∘u)(x))=u(0)=0 (1_F-u\circ v)(u(x)) =u((1_E-v\circ u)(x)) =u(0) = 0

whence u(x)∈F1u(x)\in F_1. Therefore u(E1)⊂F1u(E_1)\subset F_1; analogously, v(F1)⊂E1v(F_1)\subset E_1. The continuous linear mappings u1:E1→F1u_1: E_1\rightarrow F_1 and v1:F1→E1v_1: F_1\rightarrow E_1 induced by uu and vv are then isomorphisms inverse to one another, since v∘uv\circ u and 1E1_E (resp. u∘vu\circ v and 1F1_F) coincide on E1E_1 (resp. on F1F_1).

(iii) =⇒=\Rightarrow (ii): Let E1E_1 and F1F_1 satisfy the hypothesis of (iii). We have E1∩E_1\cap Ker(uu) ={0}=\{0\} and F1⊂F_1\subset Im(uu), hence Ker(uu) is finite-dimensional and Im(uu) is closed and of finite codimension in F. It follows from Prop. 1 of III, p. 39 that the mapping uu is a strict morphism.

(ii) =⇒=\Rightarrow (iv): Suppose condition (ii) satisfied. The closed vector subspace E2=E_2= Ker(uu) of E is finite-dimensional, and there exists a vector subspace E1E_1 of E which is a topological supplement of E2E_2 (TVS, II, p. 27, Cor. 2). The vector subspace F1=F_1= Im(uu) of F is closed and of finite codimension, and admits a topological supplement F2F_2 in F. By Prop. 1 of III, p. 39, the mapping u∣E1u|E_1 is a strict morphism, hence uu induces an isomorphism of E1E_1 onto F1F_1.

(iv) =⇒=\Rightarrow (i): Under the hypotheses of (iv), the linear mapping of F into E which coincides with u1−1u^{-1}_1 on F1F_1 and is zero on F2F_2 is a quasi-inverse of uu.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

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Cites

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Machine translation of the English, by gpt-5-6-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.