Bourbaki

Lemma 3

Tag 02V2, permanent. Cite it as [Bourbaki, Tag 02V2].

Théories spectrales, chapter III, § 6. Propriétés spectrales des endomorphismes des espaces de Banach

Let (an)n⩾0(a_n)_{n\geqslant 0} be a sequence of positive real numbers such that the power series

f(z)=∑n⩾0anzn f(z) =\sum_{n\geqslant 0}a_nz^n

has a finite radius of convergence r>0r >0. Let D⊂CD\subset \mathbf{C} be the open disc with center 0 and radius rr. There does not exist a holomorphic function f~\widetilde{f} defined on an open neighbourhood U of rr in C\mathbf{C} which coincides with ff on U∩DU\cap D.

Suppose there exists such a holomorphic function f~\widetilde{f} defined on an open neighbourhood U of rr. There exist real numbers s<rs < r and δ>0\delta >0 such that s+δ>rs+\delta > r and such that the open disk D′D' with center ss and radius δ\delta is contained in U. The power series expansion of f~\widetilde{f} at the point ss (VAR, R1, p. 26, 3.2.1) then converges for every zz in the disk with center 0 and radius δ\delta (VAR, R1, p. 29, 3.3.4). This series is

+∞(n)+∞(n)+\infty (n)+\infty (n)

f~s(z)=∑f~n\widetilde{f}_s(z) =\sum\widetilde{f}n!(s)zn=∑fn(s)z^n=\sum fn!(s)zn(s)z^n

n=0n=0n=0n=0 (VAR, R1, p. 27, 3.2.4). Since s∈Ds\in D, we have

f(n)(s)=∑k=n+∞k(k−1)⋯(k−n+1)aksk−n f^{(n)}(s) =\sum_{k=n}^{+\infty}k(k-1)\cdots (k-n+ 1)a_ks^{k-n}

(VAR, R1, p. 28, 3.2.11). Let us take zz such that 0<z<δ0< z < \delta. Since ak⩾0a_k\geqslant 0, we have

f~s(z)=∑+∞(∑+∞k(k−1)⋯n(\widetilde{f}_s(z) =\sum^{+\infty}(\sum^{+\infty}k(k-1)\cdots n(!k−n+1)aksk−n)znk-n+ 1)a_ks^{k-n})z^n

n=0k=nn=0k=n +∞k+∞+\infty k+\infty

=∑(ak∑n=\sum(a_k\sum n!(kk−kk-! nn)! sk−nzn)=∑ak(s+z)ks^{k-n}z^n)=\sum a_k(s+z)^k

k=0n=0k=0k=0n=0k=0

(TG, III, p. 40). When s+z>rs+z > r, the convergence of this expression contradicts the assumption that the radius of convergence of the power series ff is equal to rr.

Let E be a real Banach space. Let C be a pointed convex cone in E. The vector space generated by C is equal to C−CC-C (EVT, II, p. 12, cor. 1). In particular, the cone C is total in E if and only if C−CC-C is dense in E. Recall that C is said to be salient if C∩(−C)C\cap (-C) is reduced to 0 (EVT, II, p. 11).

The polar C∘C^{\circ} of C is the set of continuous linear forms ℓ∈E′\ell \in E' such that ℓ(x)⩾0\ell (x)\geqslant 0 for all x∈Cx\in C (EVT, II, p. 47, prop. 4). By the bipolar theorem (EVT, II, p. 48, th. 1), if C is a closed pointed convex cone, one has C∘∘=CC^{\circ \circ}= C.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.