Bourbaki

Lemma 5

Tag 02V8, permanent. Cite it as [Bourbaki, Tag 02V8].

Théories spectrales, chapter III, § 6. Propriétés spectrales des endomorphismes des espaces de Banach

Let E be a real Banach space, C a convex cone in E, and u∈L(E)u\in \mathscr{L}(E) such that u(C−{0})⊂C˚u(C-\{0\})\subset \mathring{C}. Let ℓ∈C∘\ell \in C^{\circ} be an eigenvector of tu^tu. Then the kernel of ℓ\ell is stable under uu and does not meet C −{0}-\{0\}.

Let λ∈R\lambda \in \mathbf{R} be such that tu(ℓ)=λℓ^tu(\ell ) =\lambda \ell. For every x∈x\in Ker(ℓ\ell ), one has

⟨u(x),ℓ⟩=⟨x,tu(ℓ)⟩=λ⟨x,ℓ⟩=0 \langle u(x), \ell \rangle =\langle x,^tu(\ell )\rangle =\lambda \langle x, \ell \rangle = 0

therefore Ker(ℓ\ell ) is stable under uu.

Let xx be a nonzero element of Ker(ℓ\ell ). For every element yy of E such that ⟨y,ℓ⟩<0\langle y, \ell \rangle <0, one has ⟨u(x)+y,ℓ⟩<0\langle u(x) +y, \ell \rangle <0, whence it follows that u(x)+u(x) + y∉Cy \notin C since ℓ∈C∘\ell \in C^{\circ}. It follows that u(x)u(x) does not belong to C˚\mathring{C}. Since u(C−{0})⊂C˚u(C-\{0\})\subset \mathring{C}, this implies that x∉Cx \notin C.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.