Bourbaki

Exercise 6, § 6

Tag 02VJ, permanent. Cite it as [Bourbaki, Tag 02VJ].

Spectral Theories, III, p. 130

Let A be a unital Z\mathbf{Z}-algebra. We suppose that A is a free Z\mathbf{Z}-module. Let B\mathscr{B} be a subset of A which is a basis of it as a Z\mathbf{Z}-module. We say that the pair (A,B)(A,\mathscr{B}) is a natural algebra if the structure constants of A with respect to B\mathscr{B} (A, III, p. 10) belong to N\mathbf{N} and if the coefficients of 1A1_A in the basis B\mathscr{B} belong to N\mathbf{N}. We say moreover that (A,B)(A,\mathscr{B}) is united if 1A1_A is an element of B\mathscr{B}.

Let (A,B)(A,\mathscr{B}) be a natural algebra. Let B0\mathscr{B}_0 be the set of the b∈Bb\in \mathscr{B} such that the coefficient of bb in 1A1_A is not zero. We denote by τA\tau_A the unique morphism of Z\mathbf{Z}-modules from A to Z\mathbf{Z} such that, for every bb in B\mathscr{B}, one has τA(b)=1\tau_A(b) = 1 if b∈B0b\in \mathscr{B}_0, and τA(b)=0\tau_A(b) = 0 otherwise.

a) One has τA(xy)=τA(yx)\tau_A(xy) =\tau_A(yx) for all (x,y)∈A2(x, y)\in A^2.

b) For all b≠b′b\not =b' in B0\mathscr{B}_0, one has b2=bb^2=b and bb′=0bb'= 0.

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.