Bourbaki

Exercise 17, § 6

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Spectral Theories, III, p. 136

Let A be a real square matrix of type (I,I)(I,I), positive and irreducible. Let y∈RIy\in \mathbf{R}^I be a proper vector of A associated with an eigenvalue α\alpha such that y≽0y\succcurlyeq 0. We then have α=r\alpha =r (with the notations of exercise 12) and y≻0y\succ 0. (Consider an extremal vector uu for tA^tA, and calculate ⟨y∣tAu⟩=⟨Ay∣u⟩.\langle y|^tAu\rangle =\langle Ay|u\rangle .)

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Machine translation of the English, by gpt-5-6. Not checked by a person.