Tag 02W5, permanent. Cite it as [Bourbaki, Tag 02W5].
Spectral Theories, III, p. 141
It is assumed in this exercise that conditions (i) to (iv) are satisfied. (a) We fix x0∈C˚. For λ∈Uf, let A(λ)= inf{M∈R+∣x(λ)≼CMx0}. Let C0∈R+ be such that f≼CC0u(x0). For every λ in Uf, the interval [λ,λ+C0/A(λ)[ is contained in Uf(cf. exercise 26, question d)).
(b) Deduce that the function λ↦A(λ) tends to +∞ when λ∈Uf tends to λm.
For every λ in Uf, we denote by x(λ)=x(λ)/A(λ).
We now suppose that condition (vi) is satisfied.
(c) Prove that the set of values of the mapping x possesses a value of adherence xm such that
0≼Cxm≼Cx0 and xm=λmu(xm).
(d) Prove that xm=0. (If we had xm=0, let U be a neighbourhood of 0 in E such that x0+U⊂C; for every μ⩾0, there would exist a sequence (λn) in Uf converging to λm such that x0−μx(λn)≽C0, in contradiction with the definition of A(λ).)
(e) Let y∈C−{0} such that y=λmu(y). Put θ= sup{γ∣γy≼Cxm}. We have θ∈R+∗ and xm=θy. (We have θy≼Cxm and θy=λmu(θy); if xm=θy, then we would have xm−θy≻C0 and there would exist ε>0 such that xm−θy≽Cεy, in contradiction with the definition of θ.)
(f) Let y∈C−{0} and μ∈R such that y=μu(y). Then we have μ=λm. (Note that 0<μ and μ⩾λm; if we had μ>λm, let θ= sup{γ∣γxm≼Cy}; we would then have θ∈R+∗, then θxm≼Cy, whence θxm=λmu(θxm)≺Cμu(θxm)≼Cμu(y)=y, in contradiction with the definition of θ.)