Bourbaki

Lemma 4

Tag 02YU, permanent. Cite it as [Bourbaki, Tag 02YU].

Théories spectrales, chapter IV, § 2. Endomorphismes normaux

Let Y and Z be locally compact topological spaces, f:X→Yf: X\rightarrow Y and g:Y→Zg: Y\rightarrow Z universally measurable mappings. The mapping g∘f:X→Zg\circ f: X\rightarrow Z is universally measurable.

Let μ\mu be a positive measure with compact support on X and let C be its support. The restriction of ff to C is (μ∣(\mu|C)-proper. The mapping gg is measurable with respect to the image measure (f∣C)(μ∣C)(f|C)(\mu|C), hence the mapping (g∘f)∣C=g∘(f∣C)(g\circ f)|C =g\circ (f|C) is (μ∣(\mu|C)-measurable. Consequently, the mapping g∘fg\circ f is μ\mu-measurable. The lemma follows.

We denote by Lu(X)\mathscr{L}_u(X) the vector space of complex-valued functions which are universally measurable on X, and by Lu∞(X)\mathscr{L}_u^{\infty}(X) the subspace of functions f∈Lu(X)f\in \mathscr{L}_u(X) which are bounded on X. For f∈Lu∞f\in \mathscr{L}_u^{\infty}(X), we put ∥f∥∞=\|f\|_{\infty}= supx∈X∣f(x)∣_{x\in X}|f(x)|.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.