Bourbaki

Remark

Tag 02ZA, permanent. Cite it as [Bourbaki, Tag 02ZA].

Théories spectrales, chapter IV, § 2. Endomorphismes normaux

Let A be a commutative unital stellar subalgebra of L(E)\mathscr{L}(E). For every xx and yy in E, let μx,y\mu_{x,y} denote the spectral measure of (x,y)(x, y) relative to A. The mapping defined by (x,y)↦μx,y(x, y)\mapsto \mu_{x,y} of E×EE\times E into M1(X(A))\mathscr{M}^1(\mathsf{X}(A)) is sesquilinear.

Let uu be a normal endomorphism of E and A the unital stellar subalgebra of L(E)\mathscr{L}(E) generated by uu. It is commutative. The space X(A)\mathsf{X}(A) is identified with Sp(uu) by the mapping χ↦χ(u)\chi \mapsto \chi (u) (lemma 10 of I, p. 109). The spectral measure μx,y\mu_{x,y} of (x,y)(x, y) relative to A is therefore identified with a measure on Sp(uu), called the spectral measure of (x,y)(x, y) relative to uu. For every function f∈Cf\in \mathscr{C} (Sp(uu)), one then has

∫fdμx,y=⟨x∣f(u)y⟩ \int f d\mu_{x,y}=\langle x|f(u)y\rangle

Sp(uu)

by def. 5 of I, p. 110.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5-6-mini, gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.