Let f be a distribution on U and g an indefinitely differentiable function on U. Let α∈Nn. One has the relation
α(α)βα−β
∂(fg)=∑∂f∂g
β
β⩽α
Proceeding by induction on ∣α∣ as in the proof of FVR, I, p. 28, prop. 2, it is enough to consider the case where ∣α∣=1. The result then follows from the calculation
⟨∂α(fg),φ⟩=⟨fg,−∂αφ⟩=⟨f,−g∂αφ⟩
=⟨f,−∂α(gφ)+φ∂αg⟩=⟨g∂αf+f∂αg,φ⟩
valid for φ∈D(U).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.