Bourbaki

Proposition 16

Tag 031D, permanent. Cite it as [Bourbaki, Tag 031D].

Théories spectrales, chapter IV, § 3. Distributions et distributions tempérées

Let p∈[1,+∞]p\in [1,+\infty ] and f∈Lp(Rn)f\in \mathscr{L}^p(\mathbf{R}^n). Then the measure f⋅μf\cdot \mu with density ff with respect to Lebesgue measure is tempered. The mapping f↦f⋅μf\mapsto f\cdot \mu of Lp(Rn)L^p(\mathbf{R}^n) into S′(Rn)\mathscr{S}'(\mathbf{R}^n) resulting is continuous.

Let qq be the conjugate exponent of pp and let r⩾0r\geqslant 0 be such that rq>nrq > n. For every x∈Rnx\in \mathbf{R}^n, let us write g(x)=(1+∥x∥)−rg(x) = (1 +\|x\|)^{-r}. The function gg belongs to Lq(Rn)\mathscr{L}^q(\mathbf{R}^n) by Prop. 3 of IV, p. 199. By Hölder's inequality, one has

∫Rn∗(1+∥x∥)−r∣f(x)∣dμ(x)⩽Nq(g)Np(f)<+∞ \int_{\mathbf{R}^n}^*(1 +\|x\|)^{-r}|f(x)|d\mu(x)\leqslant N_q(g)N_p(f)<+\infty

therefore the measure f⋅μf\cdot \mu is tempered.

Let f∈Lp(Rn)f\in L^p(\mathbf{R}^n) and φ∈S(Rn)\varphi \in \mathscr{S}(\mathbf{R}^n). Hölder's inequality implies

∣⟨f⋅μ,φ⟩∣=∣∫Rnf(x)φ(x)dμ(x)∣⩽∥f∥p∥φ∥q |\langle f\cdot \mu, \varphi \rangle |=|\int_{\mathbf{R}^n}f(x)\varphi (x)d\mu(x)|\leqslant \|f\|_p\|\varphi \|_q

and the continuity of the mapping f↦f⋅μf\mapsto f\cdot \mu then follows from Prop. 13 of IV, p. 213.

For every p∈[1,+∞]p\in [1,+\infty ], we shall identify Lp(Rn)L^p(\mathbf{R}^n) with a subspace of S′(Rn)\mathscr{S}'(\mathbf{R}^n) by the linear mapping f↦f⋅μf\mapsto f\cdot \mu.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5-mini, gpt-5.4, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.