Bourbaki

Lemma 2

Tag 032V, permanent. Cite it as [Bourbaki, Tag 032V].

Théories spectrales, chapter IV, § 4. Opérateurs partiels

Let E, F and G be normed spaces over K, F being a Banach space. Let uu be a closed partial operator from E into F and let v∈L(F;G)v\in \mathscr{L}(F; G). If there exists C∈R+C\in \mathbf{R}_+ such that

∥u(x)∥⩽C(∥x∥+∥(v∘u)(x)∥) \|u(x)\|\leqslant C(\|x\|+\|(v\circ u)(x)\|)

for every x∈x\in dom(v∘uv\circ u) == dom(uu), that is to say, if the linear mapping x↦u(x)x\mapsto u(x) from Ev∘uE_{v\circ u} into F is continuous, then v∘uv\circ u is closed.

Let us write w=v∘uw=v\circ u. Let (xn,w(xn))n∈N(x_n, w(x_n))_{n\in\mathbf{N}} be a sequence in the graph of ww which converges in E×GE\times G. Let xx be the limit of the sequence (xn)(x_n). The hypothesis implies that the sequence (u(xn))n∈N(u(x_n))_{n\in\mathbf{N}} is then a Cauchy sequence in F; it converges to an element yy of F. Since uu is closed, one has therefore x∈x\in dom(uu) and y=u(x)y=u(x). Then w(xn)=v(u(xn))w(x_n) =v(u(x_n)) tends to v(y)=v(y) = v(u(x))v(u(x)) since vv is continuous, hence the graph of ww is closed.

Let uu be a closed partial operator on a Banach space E and F a subspace of dom(uu). If F is dense in the Banach space EuE_u, then the restriction of uu to F is closable, and its closure is equal to uu. One then says that F is a core for uu.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.