Bourbaki

Remark 1

Tag 0338, permanent. Cite it as [Bourbaki, Tag 0338].

Théories spectrales, chapter IV, § 4. Opérateurs partiels

For an operator uu with dense domain on E to be symmetric, it is necessary and sufficient that one have

⟨x∣u(y)⟩=⟨u(x)∣y⟩(2) \langle x|u(y)\rangle =\langle u(x)|y\rangle \tag{2}

for every (x,y)∈(x, y)\in dom(uu)2^2. This formula in fact shows that the domain of uu is contained in that of u∗u^*, and then that u∗u^* and uu coincide on the domain of uu. In particular, it follows that ⟨x∣u(x)⟩∈R\langle x|u(x)\rangle \in \mathbf{R} for every x∈x\in dom(uu).

As will be seen in different examples, formula (2) can often be verified by a straightforward calculus. On the other hand, the exact determination of the domain of the adjoint, which alone makes it possible to know whether or not a symmetric operator is self-adjoint, may be very delicate.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.