Bourbaki

Corollary

Tag 0343, permanent. Cite it as [Bourbaki, Tag 0343].

Théories spectrales, chapter IV, § 4. Opérateurs partiels

Let E be a complex Banach space and uu a closed partial operator on E. Let ε>0\varepsilon >0.

a) For every v∈L(E)v\in \mathscr{L}(E), one has PSpε(u)⊂_{\varepsilon}(u)\subset PSpε+∥v∥(u+v)_{\varepsilon+\|v\|}(u+v);

b) Let δ>0\delta >0 and let DδD_{\delta} be the open disk with center 0 and radius δ\delta in C\mathbf{C}. One has PSpε(u)+Dδ⊂_{\varepsilon}(u) + D_{\delta}\subset PSpε+δ(u)_{\varepsilon+\delta}(u).

Let λ∈\lambda \in PSpε(u)_{\varepsilon}(u). There exists an endomorphism w∈L(E)w\in \mathscr{L}(E) such that ∥w∥<ε\|w\|< \varepsilon and λ∈\lambda \in Sp(u+wu+w) (Prop. 20). Since u+w=(u+v)+(w−v)u+w= (u+v)+(w-v) and ∥w−v∥<ε+∥v∥\|w-v\|< \varepsilon +\|v\|, one has λ∈\lambda \in PSpε+∥v∥(u+v)(_{\varepsilon+\|v\|}(u+v) (loc. cit.).

Let μ∈Dδ\mu\in D_{\delta}; one has λ+μ∈\lambda +\mu\in Sp(u+(w+μ1E)u+ (w+\mu1_E)) and ∥w+μ1E∥<ε+δ\|w+\mu1_E\|< \varepsilon +\delta, hence λ+μ∈\lambda +\mu\in PSpε+δ(u)(_{\varepsilon+\delta}(u) (loc. cit.).

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, against glossary version 34. Not checked by a person.