Let E be a complex Banach space and u a closed partial operator on E. Let ε>0.
a) For every v∈L(E), one has PSpε(u)⊂ PSpε+∥v∥(u+v);
b) Let δ>0 and let Dδ be the open disk with center 0 and radius δ in C. One has PSpε(u)+Dδ⊂ PSpε+δ(u).
Let λ∈ PSpε(u). There exists an endomorphism w∈L(E) such that ∥w∥<ε and λ∈ Sp(u+w) (Prop. 20). Since u+w=(u+v)+(w−v) and ∥w−v∥<ε+∥v∥, one has λ∈ PSpε+∥v∥(u+v)(loc. cit.).
Let μ∈Dδ; one has λ+μ∈ Sp(u+(w+μ1E)) and ∥w+μ1E∥<ε+δ, hence λ+μ∈ PSpε+δ(u)(loc. cit.).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.