Bourbaki

Definition 3

Tag 035J, permanent. Cite it as [Bourbaki, Tag 035J].

Théories spectrales, chapter IV, § 5. Opérateurs partiels normaux et théorème spectral

For every function f∈Kf\in \mathscr{K} (Sp(uu)), one defines the endomorphism f(u)f(u) of E by f(u)=fβ(b(u))f(u) =f_{\beta}(b(u)).

The mapping f↦fβf\mapsto f_{\beta} is a complex algebra morphism of K\mathscr{K} (Sp(uu)) into C\mathscr{C}(Sp(b(u)b(u))), hence the mapping f↦f(u)f\mapsto f(u) is a complex algebra morphism of K\mathscr{K} (Sp(uu)) into L(E)\mathscr{L}(E). One has f‾(u)=f(u)∗\overline{f}(u) =f(u)^* since f‾β=fβ‾\overline{f}_{\beta}=\overline{f_{\beta}}. If f⩾0f\geqslant 0 then fβ⩾0f_{\beta}\geqslant 0, hence f(u)f(u) is a positive endomorphism of E.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.