For every function f∈K (Sp(u)), one defines the endomorphism f(u) of E by f(u)=fβ(b(u)).
The mapping f↦fβ is a complex algebra morphism of K (Sp(u)) into C(Sp(b(u))), hence the mapping f↦f(u) is a complex algebra morphism of K (Sp(u)) into L(E). One has f(u)=f(u)∗ since fβ=fβ. If f⩾0 then fβ⩾0, hence f(u) is a positive endomorphism of E.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.