Bourbaki

Corollary 1

Tag 035T, permanent. Cite it as [Bourbaki, Tag 035T].

Théories spectrales, chapter IV, § 5. Opérateurs partiels normaux et théorème spectral

a) For every f∈Luf\in \mathscr{L}_u(Sp(uu)), the partial operator f(u)f(u) is normal and f(u)∗=f‾(u)f(u)^*=\overline{f}(u). Moreover, f(u)f(u) is positive if f⩾0f\geqslant 0, and self-adjoint if ff is real-valued;

b) Let k∈Nk\in \mathbf{N} and f(z)=zkf(z) =z^k for z∈z\in Sp(uu). Then f(u)=ukf(u) =u^k;

c) Let λ∈C−\lambda \in \mathbf{C}- Sp(uu) and f(z)=(λ−z)−1f(z) = (\lambda -z)^{-1} for z∈z\in Sp(uu). Then f(u)=R(u,λ)f(u) = R(u, \lambda );

d) One has β(u)=b(u)\beta (u) =b(u);

e) Let f∈Luf\in \mathscr{L}_u(Sp(uu)) and g∈Lug\in \mathscr{L}_u(Sp(uu)) be such that ∣g∣⩽1+∣f∣|g|\leqslant 1 +|f|. The domain of g(u)g(u) is a core for f(u)f(u).

In view of the spectral theorem (th. 1 of IV, p. 266), this follows from the preceding proposition combined, respectively, with:

a) lemma 2, a) of IV, p. 266, prop. 23 of IV, p. 253, and its corollary;

b) prop. 24, b) of IV, p. 255;

c) prop. 22, b) of IV, p. 252;

d) lemma 2, a) of IV, p. 266;

e) prop. 6, b) of IV, p. 232.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.