Bourbaki

Theorem 2 (Helffer–Sjöstrand)

Tag 036A, permanent. Cite it as [Bourbaki, Tag 036A].

Théories spectrales, chapter IV, § 5. Opérateurs partiels normaux et théorème spectral

Let uu be a self-adjoint partial operator on E. Let f∈D(R)f\in \mathscr{D}(\mathbf{R}) and f~∈D(C)\widetilde{f}\in \mathscr{D}(\mathbf{C}) be an almost-analytic extension of ff. Let hh be the mapping from C\mathbf{C} into L(E)\mathscr{L}(E) defined by

h(λ)=∂f~∂z(λ)R(u,λ) h(\lambda ) =\frac{\partial\widetilde{f}}{\partial z}(\lambda )R(u, \lambda )

if λ∈C−R\lambda \in \mathbf{C}-\mathbf{R} and h(λ)=0h(\lambda ) = 0 if λ∈R\lambda \in \mathbf{R}. Then hh is μ\mu-integrable on C\mathbf{C} and

f(u)=−1π∫Ch(λ)dμ(λ) f(u) =-\frac{1}{\pi}\int_{\mathbf{C}}h(\lambda )d\mu(\lambda )

The mapping hh is measurable and its support is compact. Since uu is self-adjoint, one has ∥R(u,λ)∥⩽∣I(λ)∣−1\|R(u, \lambda )\|\leqslant |\mathscr{I}(\lambda )|^{-1} for every λ∈C−R\lambda \in \mathbf{C}-\mathbf{R} (Prop. 17 of IV, p. 248). The mapping hh is therefore bounded by formula (13), and consequently it is integrable over C\mathbf{C}.

Let ε∈R+∗\varepsilon \in \mathbf{R}^*_+. Denote by Fε+F^+_{\varepsilon} (resp. Fε−F^-_{\varepsilon}) the closed set in C\mathbf{C} of the λ∈C\lambda \in \mathbf{C} such that I(λ)⩾ε\mathscr{I}(\lambda )\geqslant \varepsilon (resp. I(λ)⩽−ε\mathscr{I}(\lambda )\leqslant -\varepsilon ). One has

∫Ch(λ)dμ(λ)=\int_{\mathbf{C}}h(\lambda )d\mu(\lambda ) = limε→0(∫Fε+h(λ)dμ(λ)+∫Fε−h(λ)dμ(λ))_{\varepsilon\rightarrow 0}(\int_{F^+_{\varepsilon}}h(\lambda )d\mu(\lambda ) +\int_{F^-_{\varepsilon}}h(\lambda )d\mu(\lambda )).

Let r>0r >0 be such that the support of hh is contained in C=[−r,r]2C = [-r, r]^2. Let us denote by Rε+R_{\varepsilon}^+ the box [−2r,2r]×[ε,2r][-2r,2r]\times [\varepsilon ,2r] in C\mathbf{C}. It is a locally polyhedral subset of C\mathbf{C} (VAR, R2, 11.3, p. 48). It satisfies the following conditions:

(i) One has Rε+⊂2C∩Fε+R^+_{\varepsilon}\subset 2C\cap F^+_{\varepsilon};

(ii) The set Rε+R^+_{\varepsilon} contains the intersection of Fε+F^+_{\varepsilon} and the support of hh;

(iii) The regular boundary ∂Rε+\partial R^+_{\varepsilon} (VAR, R2, 11.3.2, p. 49) contains the segment Sε=[−r,r]+iε⊂CS_{\varepsilon}= [-r, r] +i\varepsilon \subset \mathbf{C};

(iv) One has h(λ)=0h(\lambda ) = 0 if λ∈∂Rε+−Sε\lambda \in \partial R_{\varepsilon}^+-S_{\varepsilon}.

Let dλd\lambda (resp. dλd\lambda ) denote the differential 1-form on C\mathbf{C} which is the differential of the identity mapping of C\mathbf{C} (resp. of complex conjugation). Let gg denote the function on C−R\mathbf{C}-\mathbf{R} with values in L(E)\mathscr{L}(E) such that g(λ)=f~(λ)R(u,λ)g(\lambda ) =\widetilde{f}(\lambda )R(u, \lambda ) for λ∈C−R\lambda \in \mathbf{C}-\mathbf{R}. Put ω=gdλ\omega =g d\lambda; it is a differential 1-form on C−R\mathbf{C}-\mathbf{R}, with compact support and with values in L(E)\mathscr{L}(E). Since the resolvent of uu is holomorphic (Prop. 14 of IV, p. 246), one has

dω=(∂f~∂z(λ)R(u,λ)+f~(λ)∂∂zR(u,λ))dλ∧dλ=−h(λ)dλ∧dλ d\omega =(\frac{\partial\widetilde{f}}{\partial z}(\lambda )R(u, \lambda ) +\widetilde{f}(\lambda )\frac{\partial}{\partial z}R(u, \lambda ))d\lambda \wedge d\lambda =-h(\lambda )d\lambda \wedge d\lambda

The vector measure associated with dωd\omega (VAR, R2, 10.4.3, p. 43) is the measure with density −2ih-2ih with respect to Lebesgue measure. Applying Stokes's formula to the locally polyhedral set Rε+R_{\varepsilon}^+ and to the differential form ω\omega (VAR, R2, 11.3.4, p. 49), one therefore obtains

i2∫Rε+dω=i2∫∂Rε+ω=i2∫Sεω=i2∫−rrf~(y+iε)R(u,y+iε)dy \frac{i}{2}\int_{R^+_{\varepsilon}}d\omega =\frac{i}{2}\int_{\partial R^+_{\varepsilon}}\omega =\frac{i}{2}\int_{S_{\varepsilon}}\omega =\frac{i}{2}\int_{-r}^r\widetilde{f}(y+i\varepsilon )R(u, y+i\varepsilon )dy

whence

∫Fε+h(λ)dμ(λ)=−i2∫Rf~(y+iε)R(u,y+iε)dy \int_{F^+_{\varepsilon}}h(\lambda )d\mu(\lambda ) =-\frac{i}{2}\int_{\mathbf{R}}\widetilde{f}(y+i\varepsilon )R(u, y+i\varepsilon )dy

Reasoning analogously for Fε−F^-_{\varepsilon}, one obtains

∫Fε−h(λ)dμ(λ)=−i2∫Rf~(y−iε)R(u,y−iε)dy \int_{F^-_{\varepsilon}}h(\lambda )d\mu(\lambda ) =-\frac{i}{2}\int_{\mathbf{R}}\widetilde{f}(y-i\varepsilon )R(u, y-i\varepsilon )dy

and one concludes that the integral of hh over C\mathbf{C} is the limit as ε→0\varepsilon \rightarrow 0 of

vε=i2∫R(f~(y+iε)R(u,y+iε)−f~(y−iε)R(u,y−iε))dy v_{\varepsilon}=\frac{i}{2}\int_{\mathbf{R}}(\widetilde{f}(y+i\varepsilon )R(u, y+i\varepsilon )-\widetilde{f}(y-i\varepsilon )R(u, y-i\varepsilon ))dy

By Prop. 7, one has vε=πfε(u)v_{\varepsilon}=\pi f_{\varepsilon}(u), where fεf_{\varepsilon} is the function defined on R\mathbf{R} by

fε(x)=−12iπ∫R(f~(y+iε)y−x+iε−f~(y−iε)y−x−iε)dy f_{\varepsilon}(x) =-\frac{1}{2i\pi}\int_{\mathbf{R}}(\frac{\widetilde{f}(y + i\varepsilon)}{y-x + i\varepsilon}-\frac{\widetilde{f}(y-i\varepsilon)}{y-x-i\varepsilon})dy

As fε→ff_{\varepsilon}\rightarrow f when ε→0\varepsilon \rightarrow 0 in Cb(R)\mathscr{C}_b(\mathbf{R}) (Lemma 7), the endomorphism vε=πfε(u)v_{\varepsilon}=\pi f_{\varepsilon}(u) converges to πf(u)\pi f(u) in L(E)\mathscr{L}(E) (Prop. 5 of IV, p. 275). The theorem is proved.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.