Bourbaki

Proposition 13

Tag 036L, permanent. Cite it as [Bourbaki, Tag 036L].

Théories spectrales, chapter IV, § 5. Opérateurs partiels normaux et théorème spectral

Let uu be a positive self-adjoint partial operator on E. Let quq_u be the associated positive partial form.

a) The domain of quq_u is the domain of u1/2u^{1/2}, and for all xx and yy in dom(u1/2u^{1/2}), one has qu(x,y)=⟨u1/2(x)∣u1/2(y)⟩q_u(x, y) =\langle u^{1/2}(x)|u^{1/2}(y)\rangle;

b) The positive partial form quq_u is closed. The domain of uu is a core for quq_u.

Since uu is positive, one has ∣u∣=u|u|=u. The domain dom(∣u∣1/2|u|^{1/2}) of quq_u therefore coincides with dom(u1/2u^{1/2}), and one has

qu(x,y)=∫tdμx,y(t)=∫t1/2⋅t1/2dμx,y(t) q_u(x, y) =\int t d\mu_{x,y}(t) =\int t^{1/2}\cdot t^{1/2}d\mu_{x,y}(t)

Sp(uu) Sp(uu)

=⟨u1/2(x)∣u1/2(y)⟩ =\langle u^{1/2}(x)|u^{1/2}(y)\rangle

for xx and yy in dom(quq_u) (prop. 4, b) of IV, p. 271). This proves assertion a).

Moreover, the prehilbertian space EquE_{q_u} then coincides with the prehilbertian space Eu1/2E_{u^{1/2}} associated with u1/2u^{1/2} (def. 4 of IV, p. 230). Since u1/2u^{1/2} is a closed partial operator, this space is a Hilbert space (prop. 4 of IV, p. 230) and dom(uu) is dense in Eu1/2E_{u^{1/2}} by assertion e) of cor. 1 of IV, p. 273.

Let qq be a partial hermitian form on E with domain D dense in E. For y∈Dy\in D, let us denote by λy\lambda_y the linear form x↦q(y,x)x\mapsto q(y, x) on D. We denote by D~\widetilde{D} the set of y∈Dy\in D such that the linear form λy\lambda_y is continuous on D.

Let y∈D~y\in \widetilde{D}. Since D is dense in E, there exists a unique continuous linear form on E which extends λy\lambda_y. We denote it again by λy\lambda_y. There exists a unique element u(y)u(y) in E such that λy(x)=⟨u(y)∣x⟩\lambda_y(x) =\langle u(y)|x\rangle for every x∈Ex\in E (EVT, V, p. 15, th. 3). The mapping y↦u(y)y\mapsto u(y) is linear from D~\widetilde{D} into E; the partial operator uu on E with domain D~\widetilde{D} is called the partial operator representing qq. One therefore has

q(x,y)=⟨x∣u(y)⟩ q(x, y) =\langle x|u(y)\rangle

for y∈y\in dom(uu) and x∈Dx\in D.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.