Exercise 10, § 5
Tag 037L, permanent. Cite it as [Bourbaki, Tag 037L].
Spectral Theories, IV, p. 355
Let E be a complex Hilbert space and A a self-adjoint unital subalgebra of which is closed for the topology of simple convergence. (Such an algebra is called a von Neumann algebra.)
a) There exists a subset X of such that A coincides with the commutant of X in . (Use exercise 24 of IV, p. 326.) Conversely, for every self-adjoint subset X, the commutant of X in is a self-adjoint unital subalgebra closed for the topology of simple convergence.
b) Let and let be the polar decomposition of (definition 4 of I, p. 140). The elements and belong to A.
c) Let be such that is normal. For every function (Sp()), the endomorphism belongs to A.
d) Let . The element is a divisor of 0 on the right (resp. on the left) in A (cf. A, I, p. 93) if and only if the image of is not dense in E (resp. if is not injective). e) Let F denote the set of partial operators on E whose elements are the closed partial operators with dense domain such that, for every in X, the partial operator is a restriction of the partial operator . For every in F and in A, the partial operators and belong to F.
f) Let and let be the polar decomposition of (definition 7 of IV, p. 290). The partial operator belongs to F and belongs to A.
g) Let be such that is normal. For every function (Sp()), the partial operator belongs to F; if is bounded, then belongs to A.
h) Let be injective and have dense image in E. The partial operator belongs to F.
i) For every in F, there exist elements and of A such that is injective and has dense image and . (Reduce first to the case where is self-adjoint and positive, then apply the universally measurable functional calculus to the functions and , where and are the characteristic functions of the intervals and respectively.)
j) Suppose that every injective element of A with dense image is surjective. Then the algebra A satisfies Ore's condition: whatever and in A may be, if is not a divisor of 0 (neither on the right nor on the left), then there exist and in A such that is not a divisor of 0 and .
k) The conclusion of the preceding question is not always valid. (Consider )
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